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If V is the volume of the average container size (25L jerry can?), and q is the flow rate from your outlet then t=v/q is the time taken to fill a container. The number of containers that can be filled in one hour (N) from a single outlet is then N=60/t. In the absence of data on abstraction you will have to make some assumptions on which times water mot people will collect water. I would go with something along the lines that most households will collect water in the morning, say from dawn to 8:00, or in the evenings from 3:00 until dusk. If you multiply the total number of households by the design daily water demand per household you get the total volume that needs to be supplied during your peak collection times. Divide this by your assumed collection times to figure out your peak water demand. Use a factor of safety of 20-25% due to the sweeping nature of your assumptions. I assume that because this is a class exercise your tutours will be more interested in the logic applied in deriving the figure rather than it's actual accuracy. You could check on-line form your Water Ministry, I would be very surprised if abstraction patterns from village supplies are not available.