Revision history [back]
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initial version
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To give an answer to this problem it is essential to know what volume of water is to be pumped per unit time (second, hour, day etc.).
The pump would need to be lowered Inside the well under water level, so preferably a submersible pump.
The approximately calculation formula is: Pump power P = (Height (meters) X Volume per second (meter cube per second) X 1000 (density of water in Kg per meter cube) X 9.81 (gravity constant) X efficiency of pump and motor (I suggest as a ballpark figure take 0.75)) divided by 1000 to get kilowatts of pump rating.
Remember that a solar panel produces direct current. And we need an inverter to get alternating current needed for AC motors.
Daniel Fayolle RedR Expert
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No.2 Revision
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To give an answer to this problem it is essential to know what volume of water is to be pumped per unit time (second, hour, day etc.).
The pump would need to be lowered Inside the well under water level, so preferably a submersible pump.
The approximately calculation formula is: Pump power P = (Height (meters) X Volume per second (meter cube per second) X 1000 (density of water in Kg per meter cube) X 9.81 (gravity constant) X efficiency of pump and motor (I suggest as a ballpark figure take 0.75)) divided by 1000 to get kilowatts of pump rating.
Remember that a solar panel produces direct current. And we need an inverter to get alternating current needed for AC motors.
Daniel
Fayolle
Fayolle
RedR Expert
