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There are an important rule to observe with this kind of problem: always start the largest motor first and also always make sure the full load rating of the generator is never exceeded, especially upon starting a new motor load. Remember that squirel cage induction electric motors take up to 6 times their full load current upon starting. This is why when these pump motors are fed from a "limited capacity" generator they are always started by means of assisted device like an autotransformer or a star-delta motor starter.
Another rule: never run the generator on full load permanently. Aim at 80% FL if the load is permanent. Never above 80% of generator capacity.
The type of starter is not mentionned. But I would guess they are star-delta starters, quite suitable for centrifugal pumps motors. With this kind of starter the starting current of the motor is reduced to 2 times full load current.
The method for appraising the generator size is as follows:
Starting with largest motor first: 1) 195 kVA horizontal pump, 296A FL, load on generator is 592A 2) 195 kVa pump, 296A FL, load on generator: 296 + 592A (2X296) = 888 A 3) 165 kVA horizontal pump, 250A FL, load on generator: 592 + 500A = 1092A 4) 110 kVa pump, 162A FL, load on generator: 296 + 296 + 250 + 324 = 1166 A 5) 110 kVA pump, 162 A FL, load on generator: 296+296+250+162+ 324= 1328A 6) 110 kVA pump, 162A FL, load on generator = 296+296+250+162+162+ 324 = 1490A 7) 110 kVA , 162A FL, load on generator: 296+296+250+162+162+162+324= 1652A 8) 40 kVA , 62A FL, load on generator: 296+296+250+162+162+162+162+124 (2X62)= 1614 A upon starting of last generator. Thus generator minimum size required is : 1.732X380X1614= 1062 KVA minimum.
So you would need another generator of 1062 kVA size. Preferably 1200 kVA. Or a second one of circa 500 kVA to operate in paralell with the existing one.
This calculation above is based on the assumption that all electric motors are star-delta started and that all pumps and motors run on full load.
Daniel FAYOLLE RedR Expert
2 |
No.2 Revision
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There are an important rule to observe with this kind of problem: always start the largest motor first and also always make sure the full load rating of the generator is never exceeded, especially upon starting a new motor load. Remember that squirel cage induction electric motors take up to 6 times their full load current upon starting. This is why when these pump motors are fed from a "limited capacity" generator they are always started by means of assisted device like an autotransformer or a star-delta motor starter.
Another rule: never run the generator on full load permanently. Aim at 80% FL if the load is permanent. Never above 80% of generator capacity.
The type of starter is not mentionned. But I would guess they are star-delta starters, quite suitable for centrifugal pumps motors. With this kind of starter the starting current of the motor is reduced to 2 times full load current.
The method for appraising the generator size is as follows:
Starting with largest motor first:
1) 195 kVA horizontal pump, 296A FL, load on generator is
592A
592A
2) 195 kVa pump, 296A FL, load on generator: 296 + 592A (2X296) = 888
A
A
3) 165 kVA horizontal pump, 250A FL, load on generator: 592 + 500A =
1092A
1092A
4) 110 kVa pump, 162A FL, load on generator: 296 + 296 + 250 + 324 = 1166
A
A
5) 110 kVA pump, 162 A FL, load on generator: 296+296+250+162+ 324=
1328A
1328A
6) 110 kVA pump, 162A FL, load on generator = 296+296+250+162+162+ 324 =
1490A
1490A
7) 110 kVA , 162A FL, load on generator: 296+296+250+162+162+162+324=
1652A
1652A
8) 40 kVA , 62A FL, load on generator: 296+296+250+162+162+162+162+124 (2X62)= 1614 A upon starting
of last generator.
Thus generator minimum size required is : 1.732X380X1614= 1062 KVA minimum.
So you would need another generator of 1062 kVA size. Preferably 1200 kVA. Or a second one of circa 500 kVA to operate in paralell with the existing one.
This calculation above is based on the assumption that all electric motors are star-delta started and that all pumps and motors run on full load.
Daniel
FAYOLLE
FAYOLLE
RedR Expert
3 |
No.3 Revision
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There
are
is
an important rule to observe with this kind of problem: always start the largest motor first and
also always make sure the full load rating of the generator is never exceeded, especially upon
starting a new motor load. Remember that squirel cage induction electric motors take up to 6 times
their full load current upon starting. This is why when these pump motors are fed from a "limited
capacity" generator they are always started by means of assisted device like an autotransformer or a
star-delta motor starter.
Another rule: never run the generator on full load permanently. Aim at 80% FL if the load is permanent. Never above 80% of generator capacity.
The type of starter is not mentionned. But I would guess they are star-delta starters, quite suitable for centrifugal pumps motors. With this kind of starter the starting current of the motor is reduced to 2 times full load current.
The method for appraising the generator size is as follows:
Starting with largest motor first:
1) 195 kVA horizontal pump, 296A FL, load on generator is 592A
2) 195 kVa pump, 296A FL, load on generator: 296 + 592A (2X296) = 888 A
3) 165 kVA horizontal pump, 250A FL, load on generator: 592 + 500A = 1092A
4) 110 kVa pump, 162A FL, load on generator: 296 + 296 + 250 + 324 = 1166 A
5) 110 kVA pump, 162 A FL, load on generator: 296+296+250+162+ 324= 1328A
6) 110 kVA pump, 162A FL, load on generator = 296+296+250+162+162+ 324 = 1490A
7) 110 kVA , 162A FL, load on generator: 296+296+250+162+162+162+324= 1652A
8) 40 kVA , 62A FL, load on generator: 296+296+250+162+162+162+162+124 (2X62)= 1614 A upon starting of last generator.
Thus generator minimum size required is : 1.732X380X1614= 1062 KVA minimum.
So you would need another generator of 1062 kVA size. Preferably 1200 kVA. Or a second one of circa 500 kVA to operate in paralell with the existing one.
This calculation above is based on the assumption that all electric motors are star-delta started and that all pumps and motors run on full load.
Daniel FAYOLLE
RedR Expert